HPE6-A85 Online Practice Questions and Answers

Correct Answer: A

Explanation: Aruba's Captive Portal uses Layer 3 authentication, which means that it intercepts the client's HTTP requests and redirects them to a web page where the client can enter their credentials. The credentials are then verified by a RADIUS server or a local database before granting network access. References:https://www.arubanetworks.com/techdocs/Instant_86_WebHelp/Content/instan t-ug/captive-portal/captive-portal-auth.htm

Correct Answer: C

Explanation: A slow amber-flashing Stack-LED indicates that stacking mode is selected on the switch. This means that the switch is ready to join a stack or form a new stack if no other switches are present.

References: https://www.arubanetworks.com/techdocs/ArubaOS_86_Web_Help/Content/ar ubaos-solutions/1-overview/stacking-leds.htm

Correct Answer: C

Explanation: This configuration script will achieve the task as it follows the guidelines given by the Senior Engineer. It creates VLAN 20 with name Mgmt, adds L3 SVI on VLAN 20 with IP address 10.1.1.10/24, creates LAG 1 with LACP mode active for the uplink, uses VLAN 20 as the native VLAN on the LAG, and ensures that the interfaces are all ON.

References:https://www.arubanetworks.com/techdocs/AOS-CX/10.04/HTML/5200- 6790/GUID-8F0E7E8B-0F4B-4A3C-AE7F-0F1B5A7F9C5D.html

Correct Answer: BE

Only: Daisy chain plus MAD and ring are the recommended VSF topologies for Aruba switches. They provide high availability and redundancy for the VSF stack. MAD (Multiple Active Detection) is a mechanism to detect and resolve split-brain scenarios in a VSF stack.

References: https://www.arubanetworks.com/techdocs/AOS-CX/10.04/HTML/5200- 6790/GUID-D6EF042E-EEEF-49F7-B67E-4CAC41CCB24D.html

Correct Answer: B

Explanation: The correct statement when comparing 5 GHz and 6 GHz channels with identical channel widths is that 5 GHz channels travel different distances and provide different throughputs to clients compared to 6 GHz channels. This

statement reflects the fact that higher frequency signals tend to have higher attenuation Attenuation is a general term that refers to any reduction in signal strength during transmission over distance or through an object or medium . Higher

attenuation means that higher frequency signals have shorter range and lower throughput than lower frequency signals. Some facts about this statement are:

5 GHz channels have lower frequency than 6 GHz channels, which means they have lower attenuation than 6 GHz channels.

Lower attenuation means that 5 GHz channels can travel longer distances and provide higher throughputs to clients than 6 GHz channels with identical channel widths.

However, the difference in distance and throughput between 5 GHz and 6 GHz channels may not be significant in indoor environments where there are many obstacles and reflections that affect signal propagation. The advantage of using 6

GHz channels over 5 GHz channels is that they offer more spectrum availability, less interference, and more non-overlapping channels than 5 GHz channels.

The other options are not correct because:

5 GHz channels travel the same distances and provide different throughputs to clients compared to 6 GHz channels: This option is false because 5 GHz channels do not travel the same distances as 6 GHz channels due to higher attenuation

of higher frequency signals.

5 GHz channels travel the same distances and provide the same throughputs to clients compared to 6 GHz channels: This option is false because 5 GHz channels do not travel the same distances or provide the same throughputs as 6 GHz

channels due to higher attenuation of higher frequency signals. 5 GHz channels travel different distances and provide the same throughputs to clients compared to 6 GHz channels: This option is false because 5 GHz channels do not provide

the same throughputs as

6 GHz channels due to higher attenuation of higher frequency signals.

References: https://www.wi-fi.org/discover-wi-fi/wi-fi-certified-6e

https://www.wi-fi.org/file/wi- fi-alliance-spectrum-needs-study

https://www.cisco.com/c/en/us/support/docs/wireless- mobility/wireless-lan-wlan/82068-power-levels.html

https://www.cisco.com/c/en/us/products/collateral/wireless/spectrum-expert-wi- fi/prod_white_paper0900aecd807395a9.html

Correct Answer: C

Explanation: The command that is used to set a default route to 10.4.5.1 on an Aruba CX switch when in-band management using an SVI is being used is ip route 0.0 0 0/0 10.4.5.1 . This command specifies the destination network address

(0.0 0 0) and prefix length (/0) and the next-hop address (10.4.5.1) for reaching any network that is not directly connected to the switch. The default route applies to the default VRF Virtual Routing and Forwarding. VRF is a technology that allows multiple instances of a routing table to co-exist within the same router at the same time. VRFs are typically used to segment network traffic for security, privacy, or administrative purposes. , which is used for in-band management traffic that goes through an SVI Switch Virtual Interface. SVI is a virtual interface on a switch that allows the switch to route packets between different VLANs on the same switch or different switches that are connected by a trunk link. An SVI is associated with a VLAN and has an IP address and subnet mask assigned to it12.

References: https://www.arubanetworks.com/techdocs/AOS-CX/10_08/HTML/ip_route_4100i-6000- 6100-6200/Content/Chp_StatRoute/def-rou.htm https://www.arubanetworks.com/techdocs/AOS-CX/10_08/HTML/ip_route_4100i-6000- 6100-6200/Content/Chp_VRF/vrf-overview.htm

Correct Answer: D

Explanation: The signal to noise ratio (SNR) is a measure that compares the level of a desired signal to the level of background noise. SNR is defined as the ratio of signal power to the noise power, often expressed in decibels (dB). A high

SNR means that the signal is clear and easy to detect or interpret, while a low SNR means that the signal is corrupted or obscured by noise and may be difficult to distinguish or recover3. To calculate the SNR in dB, we can use the following

formula:

SNR (dB) = Signal power (dBm) - Noise power (dBm) In this question, we are given that the noise floor measures -90 dBm (0.000000001 milliwatts) and the receiver's signal strength is -65 dBm (0.000316 milliwatts). Therefore, we can plug

these values into the formula and get:

SNR (dB) = -65 dBm - (-90 dBm) SNR (dB) = -65 dBm + 90 dBm SNR (dB) = 25 dBm Therefore, the correct answer is that the SNR is 25 dBm.

References: https://en.wikipedia.org/wiki/Signal-to-noise_ratio

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